Alice
PERLEY
(b.
abt. 1680
,
Boxford, Massachusetts Bay Colony
d.
19 July 1746
,
Thompson, Crown Colony of Connecticut
)
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PERLEY Family Genealogy
Alice PERLEY was born abt. 1680 in Boxford, Massachusetts Bay Colony. Alice PERLEY was the child of John PERLEY and Mary HOWLETT and the grandchild of: (paternal) Allen PERLEY and Susanna BOKENSON (maternal) Thomas HOWLETT and Alice FRENCH
Marriage(s) and Child(ren):
She married Samson HOWE 10 June 1710 in Boxford, Province of Massachusetts Bay . The couple had (at least) 1 child. Samson HOWE was born 13 November 1682 in Ipswich, Massachusetts, USA. He died 3 September 1736 in Killingly, Connecticut, USA (Danielson) (Dayville) (East Killingly). He was the son of Abraham HOWE and Sarah PEABODY.
Alice PERLEY died 19 July 1746 in Thompson, Crown Colony of Connecticut .
Details of the family tree of Alice appear below.
America - Did you know? January 12, 1932 - Hattie Wyatt Caraway of Arkansas is the first woman elected to the U.S. Senate,...Read MORE...www.infoplease.com
The name 'Massachusetts' originates with native Americans in the Massachusetts Bay area (from the language of the Algonquian nation). The name translates roughly as 'at or about the great hill.' (statesymbolsusa.org)1620 - 1627 - Plymouth Colony, New England
1628 - 1686 - Massachusetts Bay Colony
1686 - 1689 - Dominion of New England
1689 - 1692 - Massachusetts Bay Colony
1692 - 1775 - Province of Massachusetts Bay
1776 - 1788 - Crown Colony of Massachusetts Bay
February 6, 1788 - Massachusetts becomes 6th U.S. state
1710 Marriage / Partner
Alice PERLEY and Samson HOWE 10 June 1710, Boxford, Massachusetts, USA
1736 Death of Spouse/Partner
Samson HOWE died 3 September 1736, Killingly, Connecticut, USA (Danielson) (Dayville) (East Killingly)- 1746 Death
19 July 1746
Thompson, Connecticut, USA (North Grosvenordale) (Quinebaug)
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Added: 9/5/2016 2:44:12 PM
- Updated: 9/25/2017 8:19:04 AM
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